Question

Find the sum of first five positive integers divisible by 6

Answer 1

Hey friend. !! here's your answer
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AP

6 + 12 + .....+.30

a = 6
d = 6
l = 30
n = 5

$sn = \frac{n}{2} (a + l)d \\ \\ s5 = \frac{5}{2} (6 + 30)6 \\ \\ s5 = \frac{5}{2} (216) \\ \\ s5 = 5 \times 108 \\ \\ s5 = 540$

So that the sum of Fisrt five positive integers divisible by 6 is 540

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