.Find the sum of first ‘n’ even natural numbers.
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Answered by
13
Answer:
The sum of the first n even natural numbers is n [n + 1].
Step-by-step explanation:
Given :
First n even natural numbers are 2,4 ,6 ,………., 2n which forms an AP.
Here, a = 2, d = 4 - 2 = 2
By using the formula ,Sum of nth terms , Sn = n/2 [2a + (n – 1) d]
Sn = n/2 [2(2) + (n -1) 2]
Sn = n/2 [4 + 2n – 2]
Sn = n/2 × 2 [2 + n – 1]
Sn = n [n + 1]
Hence, the sum of the first n even natural numbers is n [n + 1].
Answered by
54
Step-by-step explanation:
n(n+1)/2
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