Math, asked by supriyaiyengarr, 7 months ago

.Find the sum of first ‘n’ even natural numbers.

Answers

Answered by DesmondMiles67
13

Answer:

The sum of the first n even natural numbers is n [n + 1].

Step-by-step explanation:

Given :  

First n even natural numbers are 2,4 ,6 ,………., 2n  which forms an AP.

Here, a = 2, d = 4 - 2 = 2

By using the formula ,Sum of nth terms , Sn = n/2 [2a + (n – 1) d]

Sn = n/2 [2(2) + (n -1) 2]

Sn = n/2  [4  + 2n – 2]

Sn = n/2 × 2 [2  + n – 1]

Sn = n [n + 1]

Hence, the sum of the first n even natural numbers is n [n + 1].

Answered by WhiteDove
54

Step-by-step explanation:

n(n+1)/2

please mark me as brainlist

Similar questions