find the sum of first n natural numbers and hence find the sum of first 20 natural numbers
please explain it and share on a photo please
step by step
class 10
chapter 3
Answers
Answered by
1
Answer:
your answer☝️
Step-by-step explanation:
solved step by step ok
and shared photo
Attachments:
Answered by
2
To Find :
- The sum of first n natural numbers =?
- The sum of first 20 natural numbers =?
Step-by-step explanation :
As We know that, the even Natural numbers are as follows -
2, 4, 6, 8, ...
So, the nth term
★ nth terms = a + ( n - 1)d
Where,
- a = first terms
- n = Total Number of given terms
- d = common Defference
So, Now keep all values
==> nth terms = 2 + (n - 1)(2)
==> nth terms = 2 + 2n - 2
==> nth terms = 2n
So, the sum of first n even Natural numbers be,
★ Sum of nth terms = n/2 (a + l)
where,
- l = last terms
keep all required values
==> Sn = n/2 (2 + 2n)
==> Sn = n (1 + n)
==> Sn = n (n + 1) [Answer]
Now, Calculate
sum of first 20 even Natural numbers be,
==> S20 = n(n + 1)
where,
- n = 20
==> S20 = 20 (20 + 1)
==> S20 = 20 × 21
==> S20 = 420 [Answer].
Hence
- The sum of first n natural numbers = n (n + 1).
- The sum of first 20 natural numbers = 420.
_______________
Similar questions