find the sum of first n term of ap √2, √8, √18, √32...
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Answer:
a = √2
d = √8-√2
= 2√2-√2 = √2
sn = n/2[ 2a +(n-1)d]
= n/2[ 2×√2 + (n-1)√2]
= n/2 [2√2 + √2n-√2]
= n/2 ×√2(2+n-1)
= n/2 × √2(n-1)
= √2n(n-1)/2
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