find the sum of first n term of the series a,3a,5a
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Answered by
4
a=a
d =2a
Sum of n terms =n/2{2a+(n-1)d}... Now in place of d.. Put 2a
Now solve it u will get the answer
d =2a
Sum of n terms =n/2{2a+(n-1)d}... Now in place of d.. Put 2a
Now solve it u will get the answer
Answered by
6
the common difference of the series will be 3a-a=2a
d=2a a=a
Sn=n/2(2a+(n-1)d)
=n/2(2a+2an-2a)
=n/2(2an)
=an^2
d=2a a=a
Sn=n/2(2a+(n-1)d)
=n/2(2a+2an-2a)
=n/2(2an)
=an^2
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