Question

find the sum of first ,nth terms of an ap √2,√8,√18 √32​

Answer 1

Given AP,

√2,√8,√18 √32

= √2 , 2√2 , 3√2 , 4√2

Common difference,

d = 2√2 - √2 = √2

a = √2

9th term,

= √2 + (9 - 1)√2

= √2 + 8√2

= 9√2

Answer 2

Step-by-step explanation:

d=✓8-✓2=2✓2-√2. =✓2

now a=✓2

SN=n/2(2a+(n-1)d)

n/2(2×✓2+(n-1)×✓2)

n/2(2✓2+2n-2)

n/✓2+n^2-n

n^2+n{1-✓2)/✓2