Question

How many moles of calcium carbonate are in 63.8g of calcium carbonate

Answer 1

0.638 moles in 63.8g of calcium carbonate

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

given mass of calcium carbonate = 63.8 g

Molar mass of calcium carbonate = 100 g/mol

$\text{Number of moles}=\frac{63.8g}{100g/mol}=0.638moles$

Thus there are 0.638 moles in 63.8g of calcium carbonate

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