find the sum of first positive numbers which are multiples of 6.
Answers
Answered by
1
The sum for first 10 multiples of 6 is>>
A.P.>>6,12,18..............60
Sn=n/2(2a+(n-1)d)
S10=10/2(2×6+(10-1)6)
S10=5(12+9×6)
S10=5(12+54)
S10=5×66
S10=330
A.P.>>6,12,18..............60
Sn=n/2(2a+(n-1)d)
S10=10/2(2×6+(10-1)6)
S10=5(12+9×6)
S10=5(12+54)
S10=5×66
S10=330
Answered by
0
The first five multiples are 6,12,18,24, 30
6+12+18+24+30
= 90
6+12+18+24+30
= 90
Similar questions