Question

Find the sum of first thirteen positive integers divisible by 6

Answer 1

6+12+18= 36 is the answer

Answer 2

hi  Hetal

the first 13 positive integers divisible by 6 are 6,12,18,....... upto 13 terms

∴the given series is in arthimetic progression with first term a=6 and common difference d=6

⇒sum of n terms of an A.p is

⇒n/2×{2a+(n-1)d}

∴ required sum = 13/2×{2(6)+(12)6}

=13/2{12+72}

=13/2×84

=13×42

=546 ANS

I hope this will help u