Math, asked by Harshharry207, 9 months ago

Find the sum of following series, 0.9,0.91,0.92,.......n terms

Answers

Answered by rajeevr06
1

Answer:

Req sum =

s_{n} =  \frac{n}{2} (2a + (n - 1)d)

 \frac{n}{2} (2 \times 0.9 + (n - 1) \times 0.01) =

 \frac{n}{2} (1.8 + 0.01n - 0.01) =

 \frac{n}{2} (1.79 + 0.01n)

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