Question

Simply: (a+b+c)2 +( a- b-c)2

Answer 1

(a+b+c)2+(a-b-c)2

2a+2b+2c+2a-2b-2c

=4a

hope it helps

Answer 2

$\green{\bold{\underline{ ☆ UPSC-ASPIRANT ☆} }}$

$\red{\bold{\underline{\underline{QUESTION:-}}}}$

Simply: (a+b+c)2 +( a- b-c)2

$\huge\bigstar\huge\tt\underline\red{ᴀɴsᴡᴇʀ }\bigstar$

$➪ {(a + b + c)}^{2} + {(a - b - c)}^{2}$

$➪{(a + b + c)}^{2} = {a}^{2} + {b}^{2} + {c}^{2} + 2ab + 2bc + 2ca$

$➪ {(a - b - c)}^{2} = {a}^{2} + {b}^{2} + {c}^{2} - 2ab + 2bc - 2ca$

Now adding both :- we get

$➪2 {a}^{2} + 2 {b}^{2} + 2 {c}^{2} + 2ab - 2ab + 2bc + 2bc + 2ca - 2ca = 2 {a}^{2} + 2 {b}^{2} + 2 {c}^{2} + 4bc$

taking 2 as common

➤➤ 2(a^2+b^2+c^2+bc)

Hope it helps you..!!!

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Thankyou:)