Find the sum of integers from 1 to 200 which are divisible by 2 or 5 but not by both.
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Answer:
Explanation:
The sum of n consecutive terms of any arithmetic sequence is n times the average term, which is the same as the average of the first and last term.
So the sum of the integers from 1 to 200 is:
200⋅1+2002=20100
The sum of the integers: 5,10,15,...,200 is:
(2005)⋅5+2002=4100
So the sum of the integers from 1 to 200 which are not divisible by 5 is:
20100−4100=16000
Step-by-step explanation:
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