Find the sum of integers wch are divisible by 2 from 11 to 100
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Hi Friend !!
Here's ur ans with solution :-
The number which is divisible by 2 from 11 to 100 forms an AP.
that is :-
12 , 14 , 16.............. 100
First term ( a ) = 12
Common difference ( d ) = 2
Last term ( an ) = 100
• an = a + ( n - 1 )d
100 = 12 + ( n - 1 ) × 2
100 = 12 + 2n - 2
100 = 10 + 2n
90 = 2n
90/2 = n
45 = n
So, there are 45 number between 11 to 100 which are divisible by 2.
Here's ur ans with solution :-
The number which is divisible by 2 from 11 to 100 forms an AP.
that is :-
12 , 14 , 16.............. 100
First term ( a ) = 12
Common difference ( d ) = 2
Last term ( an ) = 100
• an = a + ( n - 1 )d
100 = 12 + ( n - 1 ) × 2
100 = 12 + 2n - 2
100 = 10 + 2n
90 = 2n
90/2 = n
45 = n
So, there are 45 number between 11 to 100 which are divisible by 2.
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