cos4theta -cos4alpha=?
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Check it out mannnnnnn
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sssk2:
its not my question
can you please explain
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hello users ....
solution:-
we know that:
cos C - cos D = 2 sin ( C + D)/2 sin ( D - C) / 2
So, here,
cos 4θ - cos 4α = 2 sin ( 4θ + 4α)/2 * sin (4α - 4θ)/2
=2 sin { 2(2θ + 2α)/2} * sin {2(2α - 2θ)/2}
= 2 * sin (2θ + 2α) * sin ( 2α - 2θ) Answer
# hope it helps :)
solution:-
we know that:
cos C - cos D = 2 sin ( C + D)/2 sin ( D - C) / 2
So, here,
cos 4θ - cos 4α = 2 sin ( 4θ + 4α)/2 * sin (4α - 4θ)/2
=2 sin { 2(2θ + 2α)/2} * sin {2(2α - 2θ)/2}
= 2 * sin (2θ + 2α) * sin ( 2α - 2θ) Answer
# hope it helps :)
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