Question

Find the sum of k^2-k+1,-5k^2+2k-2 and 3k^2-4k+1

Answer 1

Step-by-step explanation:

$( {k}^{2} - k + 1) + ( - 5 {k}^{2} + 2k - 2) + (3 {k}^{2}\\ - 4k + 1)$

$- {k}^{2} - 3k$

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Answer 2

QUESTION:

Find the sum of k^2-k+1,-5k^2+2k-2 and 3k^2-4k+1.

ANSWER:

In order to find the sum we use the brackets.

$( {k}^{2} - k + 1) + ( - 5 {k}^{2} + 2k - 2) + (3 {k}^{2} - 4k + 1)$

we add the like terms.

In algebra, terms which have the same variable and power are called like terms.

Opening the bracket.

${k}^{2} - k + 1 - 5 {k}^{2} + 2k - 2 + 3 {k}^{2} - 4k + 1 \\ \\ = - {k}^{2} - 3k$

FINAL ANSWER :

$\huge\red{ - {k}^{2} - 3k}$

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