find the sum of last 10 terms of AP 8,10,12,14..,126
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Answer: From the last the AP is:
126, 124, 122....8
a=126 d= -2 n = 10
Sum = n/2 [2a + (n-1)d]
==> 10/2 [2×126 + 9×-2]
==> 5 [252 - 18]
==> 5×234
==>1170
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