Question

find the sum of last 40 positive integers sociable by 6????​

Answer 1

We know that the first 40 positive integers divisible by 6 are 6,12,18,....

This is an AP with a = 6 and d = 6

$\sf S40=\frac{n}{2}[2a+(n-1)d]$

$\sf S40= 20[2(6) +(40-1)6]$

$\sf =20[12+234] =4920$

Answer 2

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