find the sum of multiples of 5 lying between 84 and 719.
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Smallest multiple of 5 between 84 and 719 = 85
Largest multiple of 5 between 84 and 719 = 715
First Term = a1 = 85
Common Difference = 5
Find the number of terms:
an = a1 + (n - 1)d
715 = 85 + (n - 1)5
715 = 85 + 5n - 5
5n = 635
n = 127
Find the sum:
Sn = n/2 (a1 + an)
Sn = 127/2 (85 + 715)
Sn = 50800
Answer: The sum is 50800
TooFree:
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Answered by
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SUM=NO OF TERMS/2(FIRST TERM+LAST TERM)
FIRST TERM=85
LAST TERM= 715
NO. OF TERMS= 4+20+20+20+20+20+20+3
=127
SUM= 127(85+715)/2
= 127*800/2
=127*400
=50800
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