Question

* Find the sum of n odd numbers
1,3,5,......​

Answer 1

Let the sum of n odd numbers is Sn

Sn=1+3+5+7+9..................+2(n-1).

a=1, d=2 last term l=2(n-1)

Sn=(n/2)*(a+l)

Sn=(n/2)*(1+2n-1).

Sn=(n/2)*(2n)= n² Ans

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Answer 2

Answer:

${\huge{\mathcal{\pink{Heya::}}}}$

Sum of n odd numbers[Sn] =1,3,5,7.........2(n -1)

1st odd no.[a]=1

Common Difference [d]= 2

Last term [l] = 2(n - 1)

Sn = (n/2) × (a+l)

Sn= (n/2) × [ 1 + 2n-1]

Sn= (n/2) × (2n)

==} Sn = n²

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