Question

Find the sum of n term of the following (4-1/n)+(4-2/n) ..... can you please send me step by step solution
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Answer 1

Answer:

This is the answer

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Answer 2

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ＴＯ ＦＩＮＤ -

ｓｕｍ ｏｆ 4-1/ｎ , 4-2/ｎ ,4-3/ｎ ??

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ＳＯＬＵＴＩＯＮ -

we know that,

1+2+3+4+...........+n

= n(n+1) /2

and

1+1+1+1+1+........+n = n

here,

sum of 4-1/n ,4-2/n ,4-3/n upto nth term is :

(4+4+4+4+4..............n) + ( -1/n - 2/n ,-3/n)

= 4n - 1/n ×n ( n+1) /2

=4n - (n + 1)2

= [8n - ( n+1)] /2........(1)

By taking L. C. M of equation (1) we get,

= ( 7n - 1) /2

SO THE SUM IS (7n-1) /2

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