D. AB crystallizes in a body centred cubic lattice with
edge length 'a' equal to 387 pm. The distance
between two oppositively charged ions in the lattice
is :-
(1) 300 pm
(3) 250 pm
(2) 335 pm
(4) 200 pm
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Answer:
3^(1/2) * a=4r....where r = radius of the particle or sphere.
distance between two oppositely charged particles is = 2r= [3^(1/2) * 387]/2
=335.15 pm
hence ....335 pm
Explanation:
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