Question

find the sum of n terms of the following progression 4,7,11,14.......n=10​

Answer 1

Answer:

Here, a1=4 , a2=7

Now , n= 10. (given)

d= a2-a1 = 7-4 = 3

a = a1 = 4

Also, Sn = n/2[2a+(n-1)d]

=10/2[(2×4)+(10-1)3

=5[8+(9)3]

=5[8+27]

=5×35=175

So, Sn = 175

Answer 2

Answer:

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