Find the sum of odd numbers between 0 to 50 in AP
Answers
Answered by
0
Answer:
625
Step-by-step explanation:
sum = 1 + 3 + 5 + 7 + ......+49.
this is an A.P, whose first term(a) = 1 and last term(Tn) = 49.
common difference(d) = 3-1 = 2
Total no. of odd number lie b/w 0 and 50 = n
but,
Tn = a + (n-1)d
or, 49 = 1 + (n-1)2
or, n-1 = 48/2 =24
n = 25
hence
sum = n/2(a + Tn)
sum = 25(1 + 49)/2
sum = 25×50/2 = 25×25
sum = 625
Answered by
1
Answer:
a + ( n - 1) d = an
=> 1 + ( n - 1) 2 = 49
=> ( n - 1) 2 = 48
=> ( n - 1) = 24
=> n = 25.
So,
Sn = n/2 × ( a +l)
= 25 /2× ( 1 +49)
= 25 /2 × 50
= 25 ×25
= 62
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