Find the sum of product of zeroes of the quadratic polynomial 3x2-4x+7
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For the quadratic equation with roots, α ,β
Sum of roots = 4/3
Product of roots = 1/3 .
The quadratic equation with roots α²/β ,
β²/ α
Now,
The Sum of roots will be = α²/β + β²/ α = α³+β³/αβ
= (α + β)³-3αβ(α+β)/αβ
= (4/3)³-3(1/3)(4/3) / 1/3
= 64/27 - 4/3 / 1/3
= 64/27-36/27 / 1/3
= 28/24 * 3/1
= 28/8
= 14/4
= 7/2 .
Product of roots = (α²/β * β²/ α) = (αβ ) = 1/3 .
The quadratic equation with required roots = x²-7/2x + 1/3 = 6x² - 21x + 2
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