Math, asked by yashvithakur03, 3 months ago

find the sum of reciprocal of [ -17/19] and negative of [-190/17]

Answers

Answered by cutie08
19

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To find :

The sum of reciprocal of ( \frac {-17}{19}) and negative of  (\frac {-190}{17})

Solution :

➤ We know that, reciprocal is the multiplicative inverse of rational number.

So,

⇒ Reciprocal of   \frac {-17}{19} \: is  \frac {-19}{17}

➤ We know that, negative of negative rational number is equal to the positive value of that rational number.

So,

⇒ Negative of  \frac {-190}{17} is  \frac {190}{17}

➤ Now, sum of reciprocal of  (\frac {-17}{19}) and negative of ( \frac {-190}{17}) ,

 \frac  {-19}{17} + \frac {190}{17}

 \frac {-19 + 190}{17}

 = \frac {171}{17}

 \implies Hence, the sum of reciprocal of  (\frac {-17}{19}) and negative of  (\frac {-190}{17}) is  (\frac {171}{17}) .

____________________☆

Answered by MoonWings
27

\bf\huge{\red{▬▬▬▬▬▬▬▬▬▬▬▬}}

\bf\huge{\red{Question←:}}

\bf{\red{:→}} Find the sum of reciprocal of [ \bf\dfrac{-17}{19} ] and negative of [ \bf\dfrac{-190}{17} ].

\bf\huge{\red{▬▬▬▬▬▬▬▬▬▬▬▬}}

\bf\huge{\red{To~find←:}}

\bf{\red{:→}} The sum of reciprocal of [ \bf\dfrac{-17}{19} ] and negative of [ \bf\dfrac{-190}{17} ].

\bf\huge{\red{▬▬▬▬▬▬▬▬▬▬▬▬}}

\bf\huge{\red{Answer←:}}

\bf{\red{:→}} We know that reciprocal is the multiplicative inverse of rational number.

So,

\bf{\red{:→}} Reciprocal of \bf\dfrac{-17}{19} is \bf\dfrac{-19}{17}

\bf{\red{:→}} We know that, negative of negative rational number is equal to the positive value of the rational number.

So,

\bf{\red{:→}} \bf\dfrac{-190}{17} is \bf\dfrac{190}{17}

\bf{\red{:→}} Now,

sum of reciprocal of \bf\dfrac{-17}{19} is \bf\dfrac{-190}{17},

\bf{\red{:→}} \bf\dfrac{-19}{17} + \bf\dfrac{190}{17}

\bf{\red{:→}} \bf\dfrac{-19+190}{17}

\bf{\red{:→}} \bf\dfrac{171}{17}

\bf{\bold{\red{Hence,~the~sum~of~reciprocal~of\dfrac{-17}{19}and ~negative~}}}\bf{\bold{\red{of\dfrac{-190}{17} is \bf\dfrac{171}{17} }}}

\bf\huge{\red{▬▬▬▬▬▬▬▬▬▬▬▬}}

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