Find the sum of roots of 2x²-3x+6=0
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Given - a and b are the roots of the equation 2x²+3x+4=0.
So, a+b=(-3/2) and ab=4/2=2
Also, a and b satisfy it. That implies
2a²+3a+4=0 - ( 1 )
And
2b²+3b+4=0 - ( 2 )
Adding equations ( 1 ) and ( 2 ) , we get
2a²+3a+4 + 2b²+3b+4 = 0
2( a² + b² ) + 3( a + b ) + 8 = 0
2( a² + b² ) + 3(-3/2) + 8 = 0
2( a² + b² ) = 9/2 - 8 = - 7/2
( a² + b² ) = -7/4
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