Question

There are 2 cuboid boxes having measurements 60x40x50 and 50x50x50 .Which box requires the lesser amount of material to make

Answer 1

Answer:

This question is quite simple.

Given,

For 1st cuboidal box,

Length(l) = 60cm

Breadth(b) = 40cm

Height(h) = 50cm

Now material used for making of this box is equal to TOTAL SURFACE AREA OF CUBOIDAL.

Therefore,

Material required = 2*(l*b+b*h+h*l)

= 2(60*40+40*50+50*60)

=2(2400+2000+3000)

=2(7400)

= 14800 sq cm

Similarly use this method for other cuboidal,

Given,

Length(l)= 50 cm

Breadth(b)= 50 cm

Height(h)= 50 cm

Material required = 2(l*b+b*h+h*l)

=2(50*50+50*50+50*50)

=2(7500)

= 15000 sq cm

Comparing both values we came to know that First cuboidal box requires less material .

Answer 2

Here's your answer...hope it helps (◕‿◕)