Find the sum of series up to 50 terms 60, 54, 48, 42
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Answered by
0
Answer:
ok dude ☺️
Step-by-step explanation:
Sum of n terms = (n/2)[2a1 + d(n-1)]
Here a1 = 66, d = -6, n = 30. So
Sum of 30 terms = (30/2)[132 + -6(30–1)]
= 15(132 - 174)
= 15 * -42
= -630 Answer.
Answered by
0
Answer:
Sn=n/2(2a+(n-1)d
Step-by-step explanation:
S50=50/2(2(60)+(50-1)-6
= 25(120+49×-6)
=25(-174)
S50 = -4350
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