Question

simplify (b²+c²)-[b²-b(b+c)+c²] ​

Answer 1

Answer:

chk thiss

Step-by-step explanation:

(b2+c2)-[b2-b(b+c)+c2]

=(b2+c2)-[b2-b2-bc+c2]

=b2+c2-b2+b2+bc-c2

=b2+bc

Answer 2

Answer:

${b}^{2} + bc$

Step-by-step explanation:

$= ( {b}^{2} + {c}^{2} ) - ( {b}^{2} - {b}^{2} - bc + {c}^{2} ) \\ = ( {b}^{2} + {c}^{2} ) - ( - bc + {c}^{2} ) \\ = {b}^{2} + {c}^{2} + bc - {c}^{2} \\ = {b}^{2} + bc$