Question

Find the sum of successor of n and predecessor of n? Find the sum of successor of n and predecessor of n?

Answer 1

Explanation:

ANSWER

Successor of n=n+1.

Predecessor of n=n−1.

∴ Sum of (n+1)+(n−1),

=2n.

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Answer 2

given successor = n .It's successor is n+1 . the sum = ( n+ 1)+ ( n+1) = 2n+2= 2(n+1 ) .