Find the sum of term in the sequence 10, 17.... which lie between 100and 300
Find the sum of term in the sequence 10,17....Which lie between 100and 300
Answers
Answered by
1
Step-by-step explanation:
100–500, first multiple of 8 is 104.
From 104 to 500, there are 396 numbers.
Between 396 numbers, there 49 mutplies of 8 ( 396/8=49.5,round down)
Thus first multiple of 8 plus 49 more equals 50. There are 50 multiple of 8s between 100 and 500.
Mark As Brainest
Answered by
1
The sequence is 10 , 17 ...
a = 10
d = 7
tn = 100
a + d(n-1) = 100
90÷7 + 1 = n
We will take the greater part therefore n = 14
t14 = a + 13d
t14 = 101
tn = a + d(n-1)
300 -10÷7 + 1 = n
we will take the smaller value of n in this case n = 42
t42 = a + 41d
t42 = 297
Total terms between 100 and 300 = 42-14= 28
Sum = n/2×(a + l)
= 28÷2×(101+297)
hence
Sum = 5572
HOPE THIS HELPS PLZ APPRECIATE THE EFFORT AND MARK AS BRAINLIEST.
Similar questions