Question

find the sum of
$\frac{1}{1 - x} + \frac{ {x}^{2} }{x - 1}$
please answer fast三​

Answer 1

Step-by-step explanation:

$\large \color{crimson}{\mathfrak W\mathtt{e \: know \: \mathfrak{t}ha\mathfrak{t}}}$

${\sf \pmb {\color{green}{a² - b² = (a + b)(a - b)}}}$

$\: \: \: \:\large \sf \purple{\frac{1}{1 - x} + \frac{ {x}^{2} }{x - 1} } \\ \\ \large \sf = \: \: \: \: \: \frac{1}{1 - x} + \frac{ {x}^{2} }{ - (1 - x)} \\ \\ \large \sf= \: \: \: \: \: \: \: \frac{1}{1 - x} - \frac{ {x}^{2} }{1 - x} \: \: \: \: \: \: \\ \\ \large \sf = \: \: \: \: \: \: \: \: \: \ \: \: \: \: \frac{1 - {x}^{2} }{(1 - x)} \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \large \sf = \: \: \: \: \: \: \: \: \: \: \: \frac{ {(1)}^{2} - {(x)}^{2} }{(1 - x)} \: \: \: \: \: \: \: \\ \\ \large \sf= \: \: \: \: \: \: \: \frac{(1 + x)\cancel{(1 - x)}}{ \cancel{(1 - x)}} \: \: \: \: \\ \\ \large \sf = \: \: \: \: \: \: \: \: \: \: \: \: \: \: \underline{ \pmb{{ \pink{1 } \: \pink{+} \: \pink x} }}\: \: \: \: \: \: \: \: \: \: \: \: \: \:$

Answer 2

Answer:

here is ur attachment

Step-by-step explanation:

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