Question

FIND THE SUM OF THE A . p 1 +3+5+7--------------- up to 12 terms

Answer 1

Answer:

hey mate here is the answer

Step-by-step explanation:

a= 1

d= 2

n= 12

sn= n/2(2a+(n+1)d)

= 12/2(2*1+12-1(2)2

= 6(2+22)

= 6×24

= 144 is your answer

pls mark as brainliest

Answer 2

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FORMULA TO BE IMPLEMENTED

Sum of first n terms of an arithmetic progression

$= \displaystyle \: \frac{n}{2} [2a + (n - 1)d ]$

Where First term = a

Common Difference = d

TO DETERMINE

The sum of the Arithmetic Progression

$\sf \: {1 + 3 + 5 + 7 + ...........upto \: \: 12 \: terms}$

EVALUATION

This is an Arithmetic progression

$\sf{ \: First \: \: term = 1\: }$

$\sf \: { \: Common \: \: Difference =3 - 1 = 2 \: }$

$\sf{Number \: of \: terms = 12 }$

So the required Sum is

$= \displaystyle \: \frac{n}{2} [2a + (n - 1)d ]$

$= \displaystyle \: \frac{12}{2} [(2 \times 1) + (12 - 1) \times 2 ]$

$= 6 \times (2 + 22)$

$= 6 \times 24$

$= 144$