find the sum of the AP 25+30+35+......11th term
Answers
Answered by
4
a=25
d=5
a11=a+(10d)
= 25+10(5)
=25+50
=75
s11=n/2(a +a11)
=11/2(25+75)
=11/2(100)
=11(50)
=550
your answer is 550
hope it helps
d=5
a11=a+(10d)
= 25+10(5)
=25+50
=75
s11=n/2(a +a11)
=11/2(25+75)
=11/2(100)
=11(50)
=550
your answer is 550
hope it helps
Answered by
2
Hey !!!
a₁ = 25
a₂ = 30
n = 11
d = a2 - a1 = 30 - 25 = 5
we know a formula
sn = n/2 [2a + ( n - 1) d ]
s11 = 11/2 [( 2* 25 + ( 11 - 1) 5
=> 11 /2 [ 50 + 50 ]
=> 11* 50
=> 550
sn = 550
______________________
Hope it helps you !!!
@Rajukumar111
a₁ = 25
a₂ = 30
n = 11
d = a2 - a1 = 30 - 25 = 5
we know a formula
sn = n/2 [2a + ( n - 1) d ]
s11 = 11/2 [( 2* 25 + ( 11 - 1) 5
=> 11 /2 [ 50 + 50 ]
=> 11* 50
=> 550
sn = 550
______________________
Hope it helps you !!!
@Rajukumar111
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