Question

Find the sum of the consecutive cubes up to 17 power 3

Answer 1

hey mate here is your answer

23409 is answer of your question

with formula

Answer 2

Hey

We have :->

$\sum \: {n}^{3} = { ( \frac{n(n + 1)}{2} )}^{2}$
-> Fill in the values to get :


${1}^{3} + {2}^{3} + {3}^{3} + ... + {17}^{3} = \frac{ {17}^{2} \times {18}^{2} }{4}$

Hence, the desired value = 289 * 81 = 23409