Question

find the sum of the cubes of the first 10 natural numbers without finding the cube of each no.​

Answer 1

Answer:

3025

Step-by-step explanation:

The formula for finding the sum of cubes of 'n' numbers is

$(\frac{n(n +1)}{2} )^{2}$

Here n = 10.

Therefore, the sum is

$(\frac{10(10 + 1)}{2}) ^{2} =(\frac{10*11}{2}) ^{2} = (5*11)^{2} =55^{2}$

$55^{2} = 3025$

Hope this helps.

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Answer 2

Step-by-step explanation:

pls mark as the brainliest