Question

Find the sum of the digit of a number when it is divided bt 5,6,7 & 8 and give remainder 3, that number is also multiple of 9.​

Answer 1

Answer:

Solution 1

If k = 2, number = (840 × 2) + 3 = 1683 which is divisible by 9. Hence 1683 is the least number which when divided by 5, 6, 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder.

Step-by-step explanation:

Answer 2

Answer:

If k = 2, number = (840 × 2) + 3 = 1683 which is divisible by 9. Hence 1683 is the least number which when divided by 5, 6, 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder.

Step-by-step explanation:

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