Find the sum of the even integers from 1 to 50
Answers
Answered by
17
Answer:
650
Step-by-step explanation:
Formula: Sn= n/2 (a1+an)
(Number of terms) n=25
(First term) a1= 2
(Last term) an= 50
S25= 25/2 (2+50)
= 25/2(52)
=(52x25)/2
=650
MANUAL:
2+4+6+8+10+12+14+16...+50 =650
Answered by
4
Given : even integers from 1 to 50
To Find : Sum
Solution:
even integers from 1 to 50
= 2 , 4 , 6 , 8 , ... ______ , 48 , 50
Adding all
2 + 4 + 6 + 8 + ... _____ + 48 + 50
Taking 2 common
= 2(1 + 2 + 3 + 4 + ... ____ + 24 + 25)
∑n = n(n + 1)/2
= 2 (25)(25 + 1)/2
= 25 (26)
= 650
Sum of even integers from 1 to 50 is 650
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