Find the sum of the first 10 natural numbers
Answers
Answered by
5
step 1 address the formula, input parameters & values.
Input parameters & values:
The number series 1, 2, 3, 4, . . . . , 9, 10.
The first term a = 1
The common difference d = 1
Total number of terms n = 10
step 2 apply the input parameter values in the formula
Sum = n/2 x (a + Tn)
= 10/2 x (1 + 10)
= 110/2
1 + 2 + 3 + 4 + . . . . + 9 + 10 = 55
Therefore, 55 is the sum of positive integers upto 10.
Input parameters & values:
The number series 1, 2, 3, 4, . . . . , 9, 10.
The first term a = 1
The common difference d = 1
Total number of terms n = 10
step 2 apply the input parameter values in the formula
Sum = n/2 x (a + Tn)
= 10/2 x (1 + 10)
= 110/2
1 + 2 + 3 + 4 + . . . . + 9 + 10 = 55
Therefore, 55 is the sum of positive integers upto 10.
Answered by
12
First ten natural numbers are-1,2,3,4,5,6,7,8,9,10.
There sum =1+2+3+4+5+6+7+8+9+10=55.
This is the answer.
Hope it helps..
Please mark me as Brainliest if you like my answer.
Thanks.
There sum =1+2+3+4+5+6+7+8+9+10=55.
This is the answer.
Hope it helps..
Please mark me as Brainliest if you like my answer.
Thanks.
harshitv62:
Thanks for BRAINLIEST
Similar questions