Question

Find the sum of the first 10 natural numbers. (Using Sum formula)​

Answer 1

❤️ $\huge\underline\bold{Answer}$ ❤️

Step 1 :

address the formula, input parameters & values.

Input parameters & values:

The number series 1, 2, 3, 4, . . . . , 9, 10.

The first term a = 1

The common difference d = 1

Total number of terms n = 10

step 2 :

apply the input parameter values in the formula

Sum = n/2 x (a + Tn)

= 10/2 x (1 + 10)

= 110/2

1 + 2 + 3 + 4 + . . . . + 9 + 10 = 55

Therefore, 55 is the sum of positive integers upto 10.

Answer 2

Answer:

n/2(1 + 10)

10/2x11=55 Ans