Find the sum of the first 100,000 of natural numbers
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0
Answer:
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Answered by
0
Answer:
500000500000
Step-by-step explanation:
In this question, the formula of sum of n terms of an arithmetic progression can be applied as given below:
1,2,3,4……………..1000000
a=1
d=1
Formula: Sn=n/2 (2a+(n-1)d)••••••••••••• (1)
[n is the number of terms]
[a is the first term]
[d is the common difference]
As in this question, n is unknown, first we will have to find n, as follows:
l=a+(n-1)d
[l is the last term]
1000000=1+(n-1) 1
=> n=1000000
From eqn (1)
Sn=1000000/2(2+999999*1)
=>Sn=500000*1000001
=> Sn=500000500000
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