Math, asked by rethliecagampang, 10 hours ago

Find the sum of the first 100,000 of natural numbers

Answers

Answered by devrajbhadauria059
0

Answer:

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Answered by pratharshan8
0

Answer:

500000500000

Step-by-step explanation:

In this question, the formula of sum of n terms of an arithmetic progression can be applied as given below:

1,2,3,4……………..1000000

a=1

d=1

Formula: Sn=n/2 (2a+(n-1)d)••••••••••••• (1)

[n is the number of terms]

[a is the first term]

[d is the common difference]

As in this question, n is unknown, first we will have to find n, as follows:

l=a+(n-1)d

[l is the last term]

1000000=1+(n-1) 1

=> n=1000000

From eqn (1)

Sn=1000000/2(2+999999*1)

=>Sn=500000*1000001

=> Sn=500000500000

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