Question

find the sum of: the first 1000 positive integers. don't give useless answers....​

Answer 1

Step-by-step explanation:

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Answer 2

Let S = 1 + 2 + 3 + . . . + 1000

Using the formula Sn =n/2(a+1) for the sum of the first n terms of an AP,

we have S1000=1000/2(1+1000)=500x1001=500500

So, the sum of the first 1000 positive integers is 500500.

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