Question

Find the sum of the first 14 terms for a sequence starting with 2, ending with 120 and common difference 2.,br>

Answer 1

IT IS 777 BECAUSE I DONT EVEN KNOW

Answer 2

$sum = n \div 2 \times (2a + (n - 1)d) \\ = (14 \div 2) \times (2 \times 2 + (14 - 1) \times 2) \\ = 7(4 + (13 \times 2)) \\ = 7(4 + 26) \\ = 7 \times 30 \\ = 210$
Here is your answer, mark me as brainly.