Question

a child wishes to build up a triangular pile of toy bricks so as to have 1 brick in the top row , 2 in the second ,3 in the third and so on . if he has 100 bricks ,how many rows can be completed and how many bricks will remain un utilized?

Answer 1

We will need to calculate it. On the first 13 rows, number of bricks

= 1+2+3+4+5+....+13 = 91.

As the next row cannot be added, no. of extra bricks = 9

Note: There is no definite formula for such a problem and you need to find it by the hit and trial manner choosing a suitable number you think will be the number of bricks in the last row and then calculate.

Answer 2

hope this helpful to u
if this helpful to u than mark me as brainleist