Question

If 0.5 mole of Zn reacts with 0.92 mole of HCl then the volume of H2 liberated at NTP is

Answer 1

Zn + 2HCl = ZnCl2 + H2
0.5 0.92

if we have 0.5 moles of Zn then we required 1 mol of HCl... but we have only 0.92 moles
So HCl is limiting reagent..

if 2 moles of HCl we get 2 g H2
therefore if we have 0.92 moles we get H2
0.92 *2÷2 = 0.92 g H2