find the sum of the first 15 multiples of 8
Answers
Answered by
2
Answer:
the answer is 960
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Answered by
1
Answer:
Step-by-step explanation:
here the multiples of 8 is 8,16,24,32......
the multiples of 8 is in AP
therefore n=15, a=8, d=8
sn=n/2[2a+(n-1)d]
sn=15/2[2×8+(15-1)8]
sn=15/2[16+(14)8]
sn=15/2[16+112]
sn=15/2[128]
sn=15×64
sn=960
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