Math, asked by gaursankalp, 1 year ago

find the sum of the first 15 multiples of 8

Answers

Answered by gshuwhs

1

This is the answer............
please mark me as a brainliest

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Answered by viji18net

0

Answer:

a = 8

n = 15

d = 8

So,Sn = n/2 [2a +(n-1)d)

= 15/2 (2×8 + (14)8]

= 15/2 [16 +112]

= 15/2 [128]

= 15 [64]

= 960

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