find the sum of the first 15 multiples of 8 for class 10 th
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The multiples of 8 are 8,16,24,32…
These are in an A.P., having first term as 8 and common difference as 8.
Therefore, a=8,d=8, S
15
Sn=2n
[2a+(n−1)d]
S15=215
[2(8)+(15−1)8]=215
[16+(14)(8)]= 215×128
=960
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