Question

find the sum of the first 15 terms of the arithmetic sequence 3,6,9,12...

Answer 1

Arithmetic Progression sum

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Answer 2

Answer:

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AP= 3,6,9,12

a=3 , d=3 , n=15

Sn= n/2 [ 2a+(n-1)d]

Sn = 15/2 [ 2×3 + (15-1) 3]

Sn = 15/2 [ 6+ 42 ]

Sn= 15/2 ×48

Sn= 15× 24

Sn = 360

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