Question

Solve following quadratic equation by method of factorization x ^ 2 + 10x + 25 = 0​

Answer 1

I don't know

I don't know

I don't know

Answer 2

Answer:

-5

Step-by-step explanation:

Given;

$x {}^{2} + 10x + 25 = 0 \\ \\ by \: using \: quadric \: formulae \\ \\ x = ( - b \frac{ + }{ - } \sqrt{b {}^{2} - 4ac } \: ) \div 2a \\ x = ( - 10 \frac{ + }{ - } \sqrt{10 {}^{2} - 4(1)(25) } \: \: ) \\ \div 2(1) \\ \\ x = (- 10 \frac{ + }{ - } \sqrt{100 - 100} \: \: ) \div 2 \\ x = ( - 10 \frac{ + }{ - } 0) \div 2 \\ x = ( - 10) \div 2 \\ = > x = - 5$

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